the probability that a new microwave oven will stop working .. Nov 4, 2021 — 0.4 = 40% probability that it stops working in less than 2 years. A similar problem is given at brainly.com/question/14398287.2 answers  ·  Top answer: Using conditional probability, it is found that there is a 0.4 = 40% probability that .AP Statistic Midterm Review Flashcards. The probability that a new microwave oven will stop working in less than 2 years is 0.05. The probability that a new microwave oven is damaged during . Protein French Toast Sticks, Chapter 6-8 Key. PDFThe probability that a new microwave oven is damaged during delivery and stops working in less than 2 years is 0.04. The probability that a new microwave oven .8 pagesQuestions & answersBrainlyQuestionthe probability that a new microwave oven will stop working in less than 2 years is 0.05. the probability that a new microwave oven is damaged during delivery and stops working in less than 2 years is 0.04. the probability that a new microwave oven is damaged during delivery is 0.10. given that a new microwave oven is damaged during delivery, what is the probability that it stops working in less than 2 years?Answer · 6 votesUsing conditional probability, it is found that there is a 0.4 = 40% probability that it stops working in less than 2 years.Conditional Probability[tex]P(B|A) = frac{P(A cap B)}{P(A)}[/tex]In whichP(B|A) is the probability of event B happening, given that A happened.[tex]P(A cap B)[/tex] is the probability of both A and B happening.P(A) is the probability of A happening.In this problem:Event A: Damaged during delivery.Event B: Stops working in less than 2 years.0.1 probability of being damaged during delivery, hence [tex]P(A) = 0.1[/tex].0.04 probability of being damaged during delivery and stop working, hence [tex]P(A cap B) = 0.04[/tex]The conditional probability is:[tex]P(B|A) = frac{P(A cap B)}{P(A)} = frac{0.04}{0.1} = 0.4[/tex]0.4 = 40% probability that it stops working in less than 2 years.A similar problem is given at https://brainly.com/question/14398287MoreQuizletQuestionThe probability that a new microwave oven will stop working in less than 2 years is 0.05. The probability that a new microwave oven is damaged during delivery and stops working in less than 2 years is 0.04. TheAnswer · 0 votes0.40MoreQuizletQuestionUnit 4: 3. The probability that a new microwave oven will stop working in less than 2 years is 0.05. The probability that a new microwave ovAnswer · 0 votes(D) 0.40MoreCheggQuestion24. The probability that a new microwave oven will stop working in less than 2 years is 0.05. The probability that a new microwave oven is damaged during delivery and stops working in less than 2 years is 0.04. The probability that a new microwave oven is damaged during delivery is 0.10. Given that a new microwave oven is damaged during delivery, what is theAnswer · 0 votes24) Given that, Let A be the event that a new microwave oven will stop working in less than 2 years .MoreGauthmathQuestionThe probability that a new microwave oven will stop working in less than 2 years is 0.05. The probability that a new microwave oven is damaged during delivery and stops working in less than 2 years is 0.04. The probability that a new microwave oven is damaged dúring delivery is 0.10. Given that a new microwave oven is damaged during delivery, what is the probability that it stops working in less than 2 years? A 0.05 B 0.06 C 0.10 D 0.40 E 0.50Answer · 156 votesAnswer: .MoreNumeradeQuestion34. The probability that a new microwave oven will stop working in less than 2 years is 0.05. The probability that a new microwave oven is damaged during delivery and stops working in less than 2 years is 0.04. The probability that a new microwave oven is damaged during delivery is 0.10. Given that a new microwave oven is damaged during delivery, what is the probability that it stops working in less than 2 years?(A) 0.05(B) 0.06(C) 0.10(D) 0.40(E) 0.50Answer · 4 votesFor this question, the probability that a new microbe oven will stop working and less than 2 years is .05. The probability that a muniroven is damaged during delivery and stops working less than 2 years is 0.04, so probability that stops working 0.05 probability that it is its stops and its are therefore it's damaged. Sorry, the probability that it stops and it's damaged is 0.04 and the probability that a new microbe oven is damaged during delivery is 0.10, so the probability that it is damaged is 0.10. So what is given that a given that a new microwave oven is damaged during delivery? What is the probability that stops so the probability it stops, given that it's damaged so probability that its stops and it's damaged is so it's publie that it stops given? That is, the image is a probability that it stops and is damaged over the probability that it's damaged and given were given those 2 values a 0.04 over 0.10 and that is equal to 0.40 and that's option: choice: d,MoreNumeradeQuestionThe probability that a new microwave oven will stop working in less than 5 years is 0.05. The probability that a new microwave oven is damaged during delivery and stops working in less than 5 years is 0.044. Given that a microwave oven is damaged during delivery, what is the probability that it stops working in less than 5 years? 0.10.Use the following information for questions 26 to 76. Scores for students on the verbal portion of the SAT-I test are normally distributed with a mean of 309 and standard deviation of 16. A random sample of 36 students who took the SAT-I test is selected to represent the main group of the sample.Find the mean and standard deviation: 309, 16.The probability that the sample mean score is greater than 540 is approximately 0.0427.Last Wednesday, a random sample of 24 students were surveyed and asked how long it takes to walk from the Fretwell building to the College Education building. The survey found a sample mean of 12.3 minutes with a standard deviation of 3.2 minutes. Assuming walking times are normally distributed, which of the following is correct for a 95% confidence interval for the population mean walking time? 12.3 + (1.645)(4), 12.3 + (2.069)(3.2), 12.3 + (2.800)(3.2), 12.3 + (2.575)(4), 12.3 + (1.96)(6.5).Answer · 3 votesHey there welcome to numerate, we have the s s h, a which is basically a cycological test measuring more novation square. There is a study for the: u s: cost students, the population means 115 and the standard deviation is 30 point. So the tissue claims that the older dots at least 30 years of age have a better added tude in s s h h, a linda samples. We state the null and alternative hypothesis. So let's do a verse null and alternative hypothesis or hypothesis and our outer hypothesis. So we have a m, so we have a turn of this alternative first, so who suspect that older students have better or better of these is greater than and greater than what greater than meat, which is 115 point? That means our null hypothesis will be less than or equal to 115 point all right and in this case we're going to use a z score because we're given a population standard deviation. Okay, so let's plug in our values, equals a sample mean, is 135.2 minus 115 population mean divided by standard deviation, wh…MoreWyzantQuestionDefective units a shipment of 12 microwave ovens contains three defective units. A vending company has ordered four of these units, and because each is identically packaged, the selection will be random. What are the probabilities that (a) all four units are good, (b) exactly two units are good, and (c) at least two units are good?Answer · 0 votes12 ovens, 3 defective, 9 not defectivepick 4 at random,probability all are not defective = 4C4(9/12)(8/11)(7/10)(6/9)= (3/4)(8/11)(7/10)(2/3)= (6/11)(7/15) = 14/55 = .25454545. = about 25.5% probability of all 4 not defectiveprobability of exactly 2 not defective, and exactly 2 defective = 4C2(9/12)(8/11)(3/10)(2/9)= 4!/2!2!(3/4)(8/11)(1/15) = 6(6/11)(1/15) = 12/55 = .2181818. = about 21.8%probability of at least 2 good = P(4 good) + P(3 good) + P(2 good) = 14/55 + P(3 good) + 12/55= 26/55 + P(3 good) = 26/55 + 4C3(9/12)(8/11)(7/10)(3/9) = 26/55 + 28/55 = 54/55 = about 98.2%probability of at least 2 good = One - Probability of zero good - probability of exactly one good= 1 - 0 - 4C3(3/12)(2/11)(1/10)(9/9) = 1 - 4(3/660) = 1-4/220 = 1-1/55 = 54/55 = 98.2%MoreStudy.comQuestionA shipment of 7 microwave ovens contains 2 defective units. A restaurant buys four of these units.What is the probability of the restaurant buying at least three non defective units?Answer · 0 votesSince the problem did not give any information on the sequence in which the microwave oven units were bought, we use the concept of combination in determining its probability. To get the total number of possible outcomes, we use the combination 7C4=35.To determine the probability of buying at least three non-defective units, we must first know the probabilities of getting exactly 3 and 4 non-defective units then get their sums after. We also use the concept of combination here.• Probability of buying at least three non-defective units is P(N≥3)=P(N=3)+P(N=4).Take note that in getting the probability of buying exactly three non-defective units, we get the number of possible ways we can take 3 non-defective units from 5 defective units given by 5C3, multiplied by the number of possible ways we can take 1 from 2 defective units given by 2C1.• Probability of buying exactly three non-defective units is P(NNN)=2C1⋅5C335=2035.Meanwhile, in getting the probability of buying exactly fou…MoreStack ExchangeQuestionThere are two local factories that produce microwaves. (Conditional probability and total probability)Answer · 1 voteYou are being asked by a conditional probability. Let me first solve the problem using just notation of events. Let's define Di as the event that the i-th checked microwave is defective, and A and B the events associated with the type of factory the microwaves were bought. The desired probability isP(D2∣D1)a=P(D1∩D2)P(D1)b=P(A∩D1∩D2)+P(B∩D1∩D2)P(A∩D1)+P(B∩D1)c=P(A)P(D1∣A)P(D2∣A∩D1)+P(B)P(D1∣B)P(D2∣B∩D1)P(A∩D1)+P(B∩D1)d=P(A)P(D1∣A)P(D2∣A)+P(B)P(D1∣B)P(D2∣B)P(A)P(D1∣A)+P(B)P(D1∣B)e=P(D1∣A)P(D2∣A)+P(D1∣B)P(D2∣B)P(D1∣A)+P(D1∣B)=0.052+0.0120.05+0.01=13300(a) Definition of conditional probability. (b)Total probability theorem. (c) Multiplication rule. (d) Given A (or B), D1 and D2 are conditionally independent. (e) P(A)=P(B).I am not sure how the expressionP(X=2)1−P(X=0)=13199could represent a conditional probability. The use of a random variable like X, instead of just events, could lead us to wrong conclusions. For example, X=1 when one of the following to possibilities occur: D1…More Feedback Sabra Avocado Toast, The probability that a new microwave oven will sto. The probability that a new microwave oven is damaged during delivery and stops working in less than 2 years is 0.04. The probability that a new microwave oven .1 answer  ·  Top answer: Answer: . 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Allan Bluman · 2014 · ‎MathematicsAppliance Ownership The probability that a person owns a microwave oven is . a customer will purchase a new car is 0.30, find the probability that the . License Plate Qq, The gaming tech that may help find alien life. Jan 23, 2017 — An iconic Australian telescope has begun a major new search for ET . The mystery signals turned out to be coming from microwave ovens used . Locking Plate, Federal Register. 1980 · ‎Administrative lawOften , microwave oven manufacturers do not know the probability . Therefore , service organizations will need to purchase new instruments to comply with .Recalls & Public Health Alerts. The products. Impacted Products. 18 to 22-lb boxes containing two 9 to 11-lb. "BONELESS OVEN ROASTED CHICKEN BREAST" .Quantitative Techniques in Business, Management and Finance: .. Umeshkumar Dubey, ‎D P Kothari, ‎G K Awari · 2016 · ‎MathematicsIt is therefore important at this stage for the retailer to recalculate the probability of a microwave oven selling under the new circumstances.Pioneer woman wishful winter platter. 4 hours ago — New 2022. The Pioneer Woman Wishful Winter Holiday Trees Stoneware Platter Ree's signature Wishful Winter design in the center of the tray .